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Byju's Answer
Standard XII
Chemistry
-I Effect
Which of the ...
Question
Which of the following is the most stable carbocation intermediate?
A
⊕
C
H
2
−
N
H
2
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B
⊕
C
H
2
−
O
H
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C
⊕
C
H
2
−
C
l
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D
⊕
C
H
2
−
C
H
3
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Solution
The correct option is
C
⊕
C
H
2
−
N
H
2
Stability of carbocation is directly proportional to electron donating group.
As N and O has lone pair of electrons.
So,
⊕
C
H
2
−
N
H
2
>
⊕
C
H
2
−
O
H
As electron donating power of
N
H
2
is higher than
O
H
.
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0
Similar questions
Q.
In which of the following pairs of carbocations, the first carbocation is more stable than the second?
(i)
C
H
2
=
C
H
−
+
C
H
2
and
C
H
2
=
C
H
−
C
H
2
−
+
C
H
2
(ii)
C
H
3
−
N
H
−
+
C
H
2
and
+
C
H
2
−
O
H
(iii)
C
H
3
−
O
−
C
H
2
−
+
C
H
2
and
C
H
2
−
O
−
+
C
H
2
(iv)
C
H
3
−
+
C
H
−
C
H
2
C
H
2
C
H
3
and
C
H
3
C
H
2
−
+
C
H
−
C
H
2
C
H
3
Q.
Assertion :
C
H
3
C
H
3
|
|
C
H
3
−
C
−
C
H
2
−
B
r
+
N
a
O
H
⟶
C
H
3
−
C
−
C
H
2
−
C
H
3
|
|
C
H
3
O
H
Reason: It follows with formation of more stable carbocation.
Q.
What is the decreasing order of strength of the bases
O
H
−
,
N
H
−
2
,
H
C
≡
C
⊝
and
C
H
3
−
C
H
⊝
2
Q.
Write chemical equation for the following conversion.
C
H
3
−
C
H
2
−
C
l
into
C
H
3
−
C
H
2
−
C
H
2
−
N
H
2
.
Q.
Identify the type of the following reaction of carbon compounds.
a. CH
3
-CH
2
-CH
2
-OH → CH
3
-CH
2
-COOH
b. CH
3
-CH
2
-CH
3
→ 3CO
2
+ 4H
2
O
c. CH
3
-CH = CH -CH
3
+ Br
2
→ CH
3
-CHBr - CHBr -CH
3
d. CH
3
-CH
3
+ Cl
2
→ CH
3
-CH
2
-Cl + HCl
e. CH
3
-CH
2
-CH
2
-CH
2
-OH → CH
3
-CH
2
-CH=CH
2
+ H
2
O
f. CH
3
-CH
2
-COOH + NaOH → CH
3
-CH
2
-COO - Na
+
+ H
2
O
g. CH
3
-COOH + CH
3
-OH → CH
3
-COO- CH
3
+ H
2
O
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