Question

Which of the following is the most stable diazonium salt?

• A. ${\mathrm{CH}}_3{{\mathrm{N}}_2}^{+}{\mathrm{X}}^{–}$
• B. ${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{CH}}_2{{\mathrm{N}}_2}^{+}{\mathrm{X}}^{–}$
• C. ${\mathrm{C}}_6{\mathrm{H}}_5{{\mathrm{N}}_2}^{+}{\mathrm{X}}^{–}$
• D. ${\mathrm{CH}}_3{\mathrm{CH}}_2{{\mathrm{N}}_2}^{+}{\mathrm{X}}^{–}$

Answer 1

The correct option is C

${\mathrm{C}}_6{\mathrm{H}}_5{{\mathrm{N}}_2}^{+}{\mathrm{X}}^{–}$

The explanation of the correct option:

C. ${\mathrm{C}}_6{\mathrm{H}}_5{{\mathrm{N}}_2}^{+}{\mathrm{X}}^{–}$

• Diazo compounds are not produced by aliphatic amines.
• ${\mathrm{C}}_6{\mathrm{H}}_5{{\mathrm{N}}_2}^{+}{\mathrm{X}}^{–}$ is the most stable diazonium salt.
• Due to resonance stabilization between the benzene nucleus and N-atom, diazonium salts with aryl groups immediately connected to the nitrogen atom are the most stable.

The explanation of incorrect options:

Since, the most stable salt is ${\mathrm{C}}_6{\mathrm{H}}_5{{\mathrm{N}}_2}^{+}{\mathrm{X}}^{–}$. Therefore, options (a), (b) and (d) stand incorrect.

Hence, the correct answer is option c, ${\mathrm{C}}_6{\mathrm{H}}_5{{\mathrm{N}}_2}^{+}{\mathrm{X}}^{–}$.