Which of the following is the remainder $z (5 z^{2} - 80)$ is divided by 5z(z-4)

z

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z - 4

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5

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0

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Solution

The correct option is C $0$
$\frac{z (5 z^{2} - 80)}{5 z (z - 4)} = \frac{z \times 5 (z^{2} - 16)}{5 z (z - 4)}$

$\frac{z (5 z^{2} - 80)}{5 z (z - 4)} = \frac{5 z (z - 4) (z + 4)}{5 z (z - 4)}$

Since the polynomial $z (5 z^{2} - 80)$ is completing divisible by $5 z (z - 4) .$

The remainder $= 0.$

Hence, the answer is $0.$

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Which of the following is the remainder z(5z2−80) is divided by 5z(z-4)

The correct option is C 0z(5z2−80)5z(z−4)=z×5(z2−16)5z(z−4)z(5z2−80)5z(z−4)=5z(z−4)(z+4)5z(z−4)Since the polynomial z(5z2−80) is completing divisible by 5z(z−4).The remainder =0.Hence, the answer is 0.

Which of the following is the remainder $z (5 z^{2} - 80)$ is divided by 5z(z-4)