Which of the following is the schmidt rearrangement reaction?

R C O C l N a N_{3} - -- \to Δ R N H_{2}

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R C O N H O O C R^{'}^{-} O H - -- \to R N H_{2}

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R C O O H + N_{3} H H_{2} S O_{4} - --- \to R - N H_{2}

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R C O N H_{2} B r_{2} + 4 N a O H - ------- \to R N H_{2}

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Solution

The correct option is C $R C O O H + N_{3} H H_{2} S O_{4} - --- \to R - N H_{2}$
Carboxylic acid reacts with hydrazoic acid to form amines. This reaction is called Schmidt rearrangement.

Mechanism:
Step 1: Here, carboxylic acid was protonated and water gets eliminated to form acylium ion.

Step 2: Hydrazoic acid attacks the acylium ion to form protonated azide.

Step 3: Abstraction of proton followed by elimination of $N_{2}$ and alkyl/aryl group migration leads to the formation of isocyanate intermediate.

Step 4: Formed isocyanate gets hydrolysed to form amine and $C O_{2}$ .

Diagram:

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