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Question

Which of the following is the smallest number that leaves a remainder of 5 when divided by 7, 15, 16 and 21?


A

1500

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B

1680

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C

1600

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D

1685

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Solution

The correct option is D

1685


The smallest number that is exactly divisible by a set of numbers is the Lowest
Common Multiple of those numbers.

7= 1 × 7

15= 1 × 3 × 5

16= 1 × 2 × 2 × 2 × 2

21= 1 × 3 × 7

LCM= 3 × 7 × 5 × 2 × 2 × 2 × 2= 1680

1680 will leave a remainder 0 when divided by 7, 15, 16 and 21.

Thus, 1680+5= 1685 will leave a remainder 5.


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