1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard X
Chemistry
Electrochemical Series
Which of the ...
Question
Which of the following is the strongest oxidising agent.
A
C
l
−
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
M
n
2
+
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
M
n
O
−
4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
C
r
3
+
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is
C
M
n
O
−
4
Since, it has greater reduction potential it can be reduced easily and hence act as a stronger oxidizing agent.
Suggest Corrections
0
Similar questions
Q.
Given
E
∘
C
l
2
/
C
l
−
=
1.36
V
,
E
∘
C
r
3
+
/
C
r
=
−
0.74
V
E
∘
C
r
2
O
2
−
7
/
C
r
3
+
=
1.33
V
,
E
∘
M
n
O
−
4
/
M
n
2
+
=
1.51
V
Among the following, the strongest reducing agent is
Q.
Given,
E
0
C
r
(
3
+
)
/
C
r
=
−
0.74
V
;
E
0
M
n
O
−
4
/
M
n
2
+
=
1.51
V
E
0
C
r
2
O
2
−
7
/
C
r
3
+
=
1.33
V
;
E
0
C
l
/
C
l
−
=
1.36
V
Based on the data given above strongest oxidising agent will be
Q.
Given,
E
0
C
r
(
3
+
)
/
C
r
=
−
0.74
V
;
E
0
M
n
O
−
4
/
M
n
2
+
=
1.51
V
E
0
C
r
2
O
2
−
7
/
C
r
3
+
=
1.33
V
;
E
0
C
l
/
C
l
−
=
1.36
V
Based on the data given above strongest oxidising agent will be
Q.
Given
E
∘
C
l
2
/
C
l
−
=
1.36
V
,
E
C
r
3
+
/
C
r
=
−
0.74
V
E
C
r
2
O
2
−
7
/
C
r
3
+
=
1.33
V
,
E
∘
M
n
O
−
4
/
M
n
2
+
=
1.51
V
Among the following, the strongest reducing agent is:
Q.
Given:
E
o
C
r
3
+
/
C
r
=
−
0.74
V
;
E
o
M
n
O
−
4
/
M
n
2
+
=
1.51
V
E
o
C
r
2
O
2
+
7
/
C
r
3
+
=
1.33
V
;
E
o
C
l
/
C
l
−
=
1.36
V
Based on the data given above, the strongest oxidising agent will be:
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Electrochemical series_tackle
CHEMISTRY
Watch in App
Explore more
Electrochemical Series
Standard X Chemistry
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app