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Solubility Product

Which of the ...

Question

Which of the following is true about the solubility of AgCl in $N H_{3}$ compared to its solubility in pure water?

Greater, because of complex ion,

{[A g (N H_{3})_{2}]}_{3}^{+}

formation.

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Greater, because of greater basicity of

N H_{3}

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Lesser, because of complex ion,

{[A g (N H_{3})_{2}]}_{3}^{+}

formation.

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Lesser, because of greater basicity of

N H_{3}

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Solution

The correct option is B Greater, because of complex ion, ${[A g (N H_{3})_{2}]}_{3}^{+}$ formation.
$A g C l \to A g^{+} + C l^{-}$
$A g^{+} + 2 N H_{3} \to {[A g (N H_{3})_{2}]}_{3}^{+}$
$N H_{3}$ helps in formation of adduct and by this increasing the solubility by shifting the reaction to right side..

Suggest Corrections

Similar questions

A g C l

N H_{3} (a q .)

A g C l

N H_{3} (a q .)

A g (N H_{3})_{2}^{+}

A g C l

A g C l

{N H}_{3}

{A g}^{+}

[{A g ({N H}_{3})}_{2}^{+}]

N H_{3}

A g (N H_{3}) 2^{+}

10^{6}

A g C l

0.20 M

{N H}_{3}

K_{s p} (A g C l) = 1.7 \times 10^{- 10}

M^{2}

K_{1} = [A g {({N H}_{3})}^{+}] / [{A g}^{+}] [{N H}_{3}] = 2.33 \times 10^{3} M^{- 1}

K_{2} = [A g {({N H}_{3})}_{2}^{+}] / [A g {({N H}_{3})}^{+}] [{N H}_{3}] = 7.14 \times 10^{3} M^{- 1}

Which of the following are properties of $N H_{3}$ ?

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