The correct option is A convex for x>5.4
Obtain the second derivative and find out for what values of x it is positive.
f′(x)=15x2−162x+11
f′′(x)=30x−162
f′′(x)>0⇒30x−162>0⇒x>5.4
As f′′(x)>0 ∀ x>5.4, the function is convex for those values, and concave ∀ x<5.4