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Oxidation and Reduction

Which of the ...

Question

Which of the following is true for the given half cell reaction?
$X^{3 +} (a q) + 2 e^{-} \to X^{+} (a q); E^{o} = y V$

Standard oxidation potential = - y V

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Standard reduction potential = y V

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E_{X^{3 +} (a q) / X^{+} (a q)}^{o} = y V

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E_{X^{3 +} (a q) / X^{+} (a q)}^{o} = - y V

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Solution

The correct option is C $E_{X^{3 +} (a q) / X^{+} (a q)}^{o} = y V$
The given half cell reaction is reduction.
Thus, the standard reduction potential of half cell electrode is "y".

$Standard oxidation potential = - Standard reduction potential$
$S O P = - S R P$

Hence, the standard oxidation potential of half cell electrode is "-y".

The shorthand notation of standard reduction potential is
$E_{X^{3 +} (a q) / X^{+} (a q)}^{o} = y V$

The shorthand notation of standard oxidation potential is
$E_{X^{+} (a q) / X^{3 +} (a q)}^{o} = - y V$

Thus, (a), (b) and (c) are true.

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Similar questions

Z n^{2 +} (a q) + 2 e^{-} ⇌ Z n (s); E^{o} = - 0.762 V

C r^{3 +} (a q) + 3 e^{-} ⇌ C r (s); E^{o} = + 0.762 V

2 H^{+} (a q) + 2 e^{-} ⇌ H_{2} (g); E^{o} = + 0.00 V

F e^{3 +} (a q) + e^{-} ⇌ F e^{2 +} (a q); E^{o} = + 0.770 V

E^{0}

S n^{4 +} (a q) + 4 e^{-} \to S n (s)

E^{0}

S n^{4 +} (a q) + 2 e^{-} \to S n^{2 +} (a q); E^{0} = 0.15 V

S n^{2 +} (a q) + 2 e^{-} \to S n (s); E^{0} = - 0.14 V

C u_{(s)} \to C u_{(a q)}^{2 +} + 2 e^{-}; E^{o} = - 0.325 V

C u_{(a q)}^{+} + e^{-} \to C u_{(s)}; E^{o} = 0.50 V

E^{o}

2 C u_{(a q)}^{+} \to C u_{(a q)}^{2 +} + C u_{(s)}

F_{2} (g) + 2 e^{-} \to 2 F^{-} (a q); E^{0} = 2.87 V C l_{2} (g) + 2 e^{-} \to C l^{-} (a q); E^{0} = 1.36 V F e^{3 +} (a q) + e^{-} \to F e^{2 +} (a q); E^{0} = 0.77 V

F_{2} (g) + 2 e^{-} \to 2 F^{-} (a q); E^{0} = 2.87 V C l_{2} (g) + 2 e^{-} \to C l^{-} (a q); E^{0} = 1.36 V F e^{3 +} (a q) + e^{-} \to F e^{2 +} (a q); E^{0} = 0.77 V

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