L = {wxwR∣x,wϵ(0,1)+} is regular, Put w as 0 and 1 which are its minimal string values and get a minimal expression
r = [0(0+1)+0]+[1(0+1)+1]
Now putting w as any other string will not create any new string not generated by r.
Example if we put w as say 01, then wxwR=01(0+1)+10 which is already generated by the first part of r
Similarly if we put w as say 10, then wxwR=10(0+1)+01 which is already generated by the second part of r
So, L = L(r)
So the regular expression for L is
r = [0(0+1)+0]+[1(0+1)+1]
That is, L reduces to the language of words which starts and ends with the same symbol. since we are able to write a regular expression for L therefore L is regular.