(i) In the given sequence, we have:
t1 = 1, t2 = 3, t3 = 6 and t4 = 10
Thus, we get:
t2 – t1 = 3 – 1 = 2
t3 – t2 = 6 – 3 = 3
t4 – t3 = 10 – 6 = 4
Because the difference between any two consecutive terms is not constant, the given sequence is not an arithmetic progression.