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Standard X

Chemistry

Chemical Reactions

Which of the ...

Question

Which of the following methods is adopted for preparing dilute solution of $H_{2} S O_{4}$ ?

Addition of

c o n c . H_{2} S O_{4}

to water

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Addition of water to

c o n c . H_{2} S O_{4}

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Dissolution of

S O_{3}

in excess water

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Dissolution of

S O_{3}

in excess

H_{2} S O_{4}

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Solution

The correct option is A Addition of $c o n c . H_{2} S O_{4}$ to water
The right method to make concentrated acid dilute is to mix acid in water. If we mix water in concentrated acid, it may cause an explosion as the reaction is exothermic.
So, for preparing dilute solution of $H_{2} {S O}_{4}$ we proceed by adding Conc. $H_{2} {S O}_{4}$ to water.

Suggest Corrections

Similar questions

Q. Which of the following methods is adopted for preparing dilute solution of

H_{2} S O_{4}

Q. Addition of

c o n c . H_{2} S O_{4}

to water is:

Q. Oleum is considered as a solution of

S O_{3}

H_{2} S O_{4}

, which is obtained by passing

S O_{3}

in solution of

H_{2} S O_{4}

. When

100 g

sample of oleum is diluted with desired weight of

H_{2} O

, the total mass of

H_{2} S O_{4}

will be for example, a oleum bottle labelled as

109 %

H_{2} S O_{4}

, means the

109

g total mass of pure

H_{2} S O_{4}

will be formed when

100

g of oleum is diluted by

9 g

H_{2} O

, which combines with all the free

S O_{3}

to form

H_{2} S O_{4}

S O_{3} + H_{2} O \to H_{2} S O_{4}

.

What is the

%

of free

S O_{3}

in an oleum that is labelled as

104.5 %

H_{2} S O_{4}

Q. Oleum is considered as a solution of

S O_{3}

H_{2} S O_{4}

, which is obtained by passing

S O_{3}

in solution of

H_{2} S O_{4}

. When 100 g sample of oleum is diluted with desired mass of

H_{2} O

then the total mass of

H_{2} S O_{4}

obtained after dilution is known as % labelling in oleum.
For example, a oleum bottle labelled as '109 %

H_{2} S O_{4}

' means the 109 g total mass of pure

H_{2} S O_{4}

will be formed when 100 g of oleum is diluted by 9 g of

H_{2} O

which combines with all the free

S O_{3}

present in oleum to form

H_{2} S O_{4}

S O_{3} + H_{2} O \to H_{2} S O_{4}

.

What is the % of free

S O_{3}

in an oleum that is labelled as '104.5 %

H_{2} S O_{4}

Q. In the preparation of

H_{2} S O_{4}

by Contact Process, why is

S O_{3}

not absorbed directly in water to form

H_{2} S O_{4}

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Which of the following methods is adopted for preparing dilute solution of H2SO4?

Which of the following methods is adopted for preparing dilute solution of $H_{2} S O_{4}$ ?