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Byju's Answer

Standard XII

Chemistry

Sulphuric Acid

Which of the ...

Question

Which of the following methods is adopted for preparing dilute solution of $H_{2} S O_{4}$ ?

Addition of conc.

H_{2} S O_{4}

to water.

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Addition of water to conc.

H_{2} S O_{4}

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Dissolution of

S O_{3}

in excess water.

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Dissolution of

S O_{3}

in excess

H_{2} S O_{4}

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Solution

The correct option is A Addition of conc. $H_{2} S O_{4}$ to water.
One should add conc. $H_{2} S O_{4}$ slowly to water to make it dilute rather than adding water to conc. $H_{2} S O_{4}$ as it is dangerous.

Suggest Corrections

Similar questions

Q. Manufacture of sulphuric acid by contact process involves dissolution of

S O_{3}

H_{2} S O_{4}

and not in water. Justify.

Q. Addition of conc.

H_{2} S O_{4}

to water is:

Q. Oleum is considered as a solution of

S O_{3}

H_{2} S O_{4}

, which is obtained by passing

S O_{3}

in solution of

H_{2} S O_{4}

. When

100 g

sample of oleum is diluted with desired weight of

H_{2} O

, the total mass of

H_{2} S O_{4}

will be for example, a oleum bottle labelled as

109 %

H_{2} S O_{4}

, means the

109

g total mass of pure

H_{2} S O_{4}

will be formed when

100

g of oleum is diluted by

9 g

H_{2} O

, which combines with all the free

S O_{3}

to form

H_{2} S O_{4}

S O_{3} + H_{2} O \to H_{2} S O_{4}

.

What is the

%

of free

S O_{3}

in an oleum that is labelled as

104.5 %

H_{2} S O_{4}

Q. In the preparation of

H_{2} S O_{4}

by Contact Process, why is

S O_{3}

not absorbed directly in water to form

H_{2} S O_{4}

Q. Oleum is considered as a solution of

S O_{3}

H_{2} S O_{4}

, which is obtained by passing

S O_{3}

in solution of

H_{2} S O_{4}

. When 100 g sample of oleum is diluted with desired mass of

H_{2} O

then the total mass of

H_{2} S O_{4}

obtained after dilution is known as % labelling in oleum.
For example, a oleum bottle labelled as '109 %

H_{2} S O_{4}

' means the 109 g total mass of pure

H_{2} S O_{4}

will be formed when 100 g of oleum is diluted by 9 g of

H_{2} O

which combines with all the free

S O_{3}

present in oleum to form

H_{2} S O_{4}

S O_{3} + H_{2} O \to H_{2} S O_{4}

.

What is the % of free

S O_{3}

in an oleum that is labelled as '104.5 %

H_{2} S O_{4}

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Which of the following methods is adopted for preparing dilute solution of H2SO4?

The correct option is A Addition of conc. H2SO4 to water.One should add conc. H2SO4 slowly to water to make it dilute rather than adding water to conc. H2SO4 as it is dangerous.

Which of the following methods is adopted for preparing dilute solution of $H_{2} S O_{4}$ ?

The correct option is A Addition of conc. $H_{2} S O_{4}$ to water.
One should add conc. $H_{2} S O_{4}$ slowly to water to make it dilute rather than adding water to conc. $H_{2} S O_{4}$ as it is dangerous.