Which of the following molecular orbital is symmetric with energy lower than combining atomic orbitals?

σ 2 s

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π^{*} 2 p_{y}

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σ 2 p_{z}

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π^{*} 2 p_{x}

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Solution

The correct options are
A $σ 2 s$
C $σ 2 p_{z}$
$s$ and $p_{z}$ orbitals are symmetric along the molecular axis and bonding orbitals have lower energy than the corresponding atomic orbitals from which they are formed.
Therefore $σ 2 s$ and $σ 2 p_{z}$ are correct
Hence, $A$ and $C$ are correct options.

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Similar questions

σ (1 s) < σ^{*} (1 s) < σ (2 s) < σ^{*} (2 s) < [π (2 p_{y}) π (2 p_{z})] < σ (2 p_{x}) < [π^{*} (2 p_{y}) π^{*} (2 p_{z})] < σ^{*} (2 p_{x})

σ_{2 S}

L i_{2}

σ^{*} 1 s, σ^{*} 2 s, σ 1 s, π 2 p_{y}, π^{*} 2 p_{x}, π^{*} 2 p_{z}, π 2 p_{z}

O_{2}

O_{2}^{-}

2 p_{x} + 2 p_{x}

2 p_{x}

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