wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Which of the following molecule doesn't have dπpπ bonding?

A
SO2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
P4O10
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
H3PO4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
B3N3H6
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D B3N3H6
The structural study of B3N3H6 shows that it has hexagonal ring with alternating B and N atom along with H atom. Each B and N are sp2 hybridized and form three sigma bond one to terminal H atom and two to the adjacent N or B atom. There is a pπ-pπ donation of filled nitrogen pz atomic orbital to adjacent Boron pz atomic orbitals. So, borazine contain 3 pi and 12 sigma bonds. Hence, there is no involvement of any d-orbital in hybridization of B3N3H6.
120978_75425_ans_d319554f3bd747709e722663f30c4bee.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction to Chemical Bonding
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon