Question

Which of the following molecule has a see-saw geometry ?

• A. $I_3^{-}$
• B. $IC{l}_2^{-}$
• C. $Cl{F}_3^{-}$
• D. $I{O}_2{F}_2^{-}$

Answer 1

The correct option is D $I{O}_2{F}_2^{-}$

$H=\frac{1}{2}[V+M-C+A]$
where,
H= Number of orbitals involved in hybridization.
V=Valence electrons of central atom.
M- Number of monovalent atoms linked to central atom.
C= Charge of cation.
A= Charge of anion.
Consider the hybridization and shape of the options:-
A) $I_3^{-}$
$H=\frac{1}{2}[7+2+1]=5$.
$\Rightarrow s{p}^{3}d$ hybridized state.
Linear in shape.
B) $IC{l}_2^{-}$
$H=\frac{1}{2}[7+2+1]=5$.
$\Rightarrow s{p}^{3}d$ hybridized state.
Linear in shape.
C) $Cl{F}_3^{-}$
$H=\frac{1}{2}[7+3]=5$.
$\Rightarrow s{p}^{3}d$ hybridized state.
T shape.
D) $I{O}_2{F}_2^{-}$
$H=\frac{1}{2}[7+2+1]=5$.
$\Rightarrow s{p}^{3}d$ hybridized state.
See Saw shape.
Hence option D is the right answer.