Which of the following molecule is having least ionic character?

F e C l_{2}

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Z n C l_{2}

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M g C l_{2}

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N a C l

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Solution

The correct option is A $F e C l_{2}$
Difference of E.N. for $A$ is less than any other compound so it would be less ionic.
$F e C l_{2}$ $3.16 - 1.91 = 1.25$ A
$Z n C l_{2}$ $3.16 - 1.65 = 1.51$ B
$M g C l_{2}$ $3.16 - 1.31 = 1.85$ C
$N a C l$ $3.16 - .93 = 2.23$ D

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