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Question

Which of the following molecules contain odd electron bonds?

A
H2O
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B
NO
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C
NO2
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D
ClO2
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Solution

The correct options are
B NO
C NO2
D ClO2

NO2

Nitrogen dioxide is the chemical compound with the formula NO2. Again, nitrogen dioxide does not follow the octet rule for one of its atoms, namely nitrogen.

The total number of valence electrons is 5+2(6)=17

There is the persistent radical character on nitrogen because it has an unpaired electron.

ClO2

A Lewis structure shows ClO2 has a total of 2×6+7=19 valence electrons, or 9 electron pairs and a lone electron.

Cl is the central atom.

The molecule ClO2 has an odd number of valence electrons.

NO

14 valence electrons in your trial structure.

The valence electrons you have available are: 1N+1O=1×5+1×6=11.

The molecule NO, NO2 and ClO2 has an odd number of valence electrons.


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