Which of the following molecules do not have regular geometry?

I F_{5}

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C H_{4}

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B F_{3}

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C C l_{4}

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Solution

The correct option is B $I F_{5}$
In $I F_{5}$ , Iodine makes $5$ covalent bonds with fluorine, with a lone pair on Iodine. So hybridization is $s p^{3} d^{2}$ and molecular geometry is distorted octahedral due to lone pair. Its shape is square pyramidal.
So, $I F_{5}$ shows Berry-Pseudorotation which is the rapid exchange of the axial and equatorial ligands.
Due to which it does not have a regular geometry.

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