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Shape and Geometry Using VSEPR

Which of the ...

Question

Which of the following molecules do not have regular geometry?
i. $I F_{5}$ ii. $H_{2} O$
iii. $B F_{3}$ iv. $C C l_{4}$

I, I V

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I, I I

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I, I I I

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I I, I V

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Solution

The correct option is A $I, I I$
Answer $B .$
In $I F_{5}$ iodine makes $5$ covalent bond with $F$ .
On central atom, there is a lone pair. So its hybridisation is $s p^{3} d^{2}$ and geometry is distorted octahedral due to lone pair.
$B F_{3}$ has $6$ valence electrons and no lone pairs and has a trigonal geometry with symmetric charge distribution.
$C C l_{4}$ has no lone pair of electrons on central carbon and is having regular tetrahedral geometry.
$H_{O}$ has a bent $V - s h a p e$ geometry with $2$ lone pair of electrons.
Hence, $I F_{5}$ and $H_{2} O$ have distorted structures.

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