Question

Which of the following molecules has hybridization involving d-orbitals?

• A. $S{F}_4$
• B. $Xe{F}_2$
• C. $Cl{F}_3$
• D. All of the above

Answer 1

The correct option is D All of the above

$S$ has 1 lone pair and four bond pairs. So, steric number of $S$ is 5 and hybridisation is $s{p}^{3}d$. Hence, the geometry of $S{F}_4$ is trigonal bipyramidal and the shape is see-saw.


$Xe$ has 3 lone pairs and two bond pairs. So, the steric number of $Xe$ is 5 and the hybridisation is $s{p}^{3}d$. Hence, the geometry of $Xe{F}_2$ is trigonal bipyramidal and the shape is linear.

$Cl$ has 2 lone pairs and 3 bond pairs. So, the steric number of $Cl$ is 5 and the hybridisation is $s{p}^{3}d$. Hence, the geometry of $Cl{F}_3$ is trigonal bipyramidal and the shape is T-shaped.