Question

Which of the following molecules is formed by ${\text{sp}}^2$ hybrid orbitals?

• A. $C{H}_4$
• B. $C{O}_2$
• C. $B{F}_3$
• D. $Be{F}_2$

Answer 1

Answer: (C)

$B{F}_3$

In ground state, boron has $2$ electrons in $s$ orbital and $1$ electron in $p$ orbital, in excited state one electron jump from $s$ to $p$ orbital and thus we get $3$ atomic orbitals for bonding which have unpaired electrons.

$1$ $s$ and $2$ $p$,

Thus, $B{F}_3$ forms three $s{p}^2$ hybridized orbitals.

So the correct option is [C].