Which of the following molecules represents the order of hybridisation $s p^{2}$ , $s p^{2}$ , $s p$ , $s p$ from left to right?

{CH}_{2} = CH - CH = {CH}_{2}

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{CH}_{2} = CH - C \equiv CH

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CH \equiv C - C \equiv CH

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{CH}_{3} - CH = CH - {CH}_{3}

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Solution

The correct option is B ${CH}_{2} = CH - C \equiv CH$
Number of orbitals required for hybridization = Number of $σ$ -bonds around each carbon atom.

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Similar questions

A straight chain hydrocarbon has the molecular formula C8H10. The hybridisation for the carbon atoms from one end of the chain to the other are respectively $s p^{3}, s p^{2}, s p^{2}, s p^{3}, s p^{2}, s p^{2}, s p$ and $s p$ . The structural formula of the hydrocarbon would be

Q. The correct order of C - H bond length in

C H_{3} - C H_{3}, C H_{2} = C H_{2}

and

C H \equiv C H

is:

Q. Which will undergo reaction with ammonical

A g N O_{3}

In the molecule CH ≡ C -CH = $C H_{2}$ , the hybridisation of C -Cbond is

C_{2}

and

C_{3}

atoms in

C H \equiv C - C H = C H_{2}

are respectively

s p

and

s p^{2}

hybridised.

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Which of the following molecules represents the order of hybridisation sp2, sp2, sp, sp from left to right?

The correct option is B CH2=CH−C≡CHNumber of orbitals required for hybridization = Number of σ-bonds around each carbon atom.

Which of the following molecules represents the order of hybridisation $s p^{2}$ , $s p^{2}$ , $s p$ , $s p$ from left to right?

The correct option is B ${CH}_{2} = CH - C \equiv CH$
Number of orbitals required for hybridization = Number of $σ$ -bonds around each carbon atom.