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Ores and Minerals

Which of the ...

Question

Which of the following not represents redox reactions?
I. ${C r}_{2} O_{7}^{2 -} + 2 ⊖ O H ⟶ 2 C r O_{4}^{2 -} + H_{2} O$
II. $Z n + C u S O_{4} ⟶ Z n S O_{4} + C u$
III. $2 M n O_{4}^{⊖} + 3 {M n}^{2 +} + 4 ⊖ O H ⟶ 5 M n O_{2} + 2 H_{2} O$
IV. $2 {C u}^{\oplus} ⟶ C u + {C u}^{2 +}$

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I, III

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III, IV

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II, III, IV

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Solution

The correct option is A I
The redox reactions are given below:
I. ${C r}_{2} O_{7}^{2 -} + 2 ⊖ O H ⟶ 2 C r O_{4}^{2 -} + H_{2} O$
+6 +6 (no change in oxidation state)
II. $Z n + C u S O_{4} ⟶ Z n S O_{4} + C u$
0 +2 +2 0 (redox reaction)
III. $2 M n O_{4}^{⊖} + 3 {M n}^{2 +} + 4 ⊖ O H ⟶ 5 M n O_{2} + 2 H_{2} O$
+7 +2 +4 (redox reaction)
IV. $2 {C u}^{\oplus} ⟶ C u + {C u}^{2 +}$
+1 0 +2 (redox reaction)
So, only II, III and IV are redox reactions.

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Similar questions

{C r}_{2} O_{7}^{2 -} + 2 ⊖ O H ⟶ 2 C r O_{4}^{2 -} + H_{2} O

Z n + C u S O_{4} ⟶ Z n S O_{4} + C u

2 M n O_{4}^{⊖} + 3 {M n}^{2 +} + 4 ⊖ O H ⟶ 5 M n O_{2} + 2 H_{2} O

2 {C u}^{\oplus} ⟶ C u + {C u}^{2 +}

C u^{+} \to C u^{2 +} + C u

3 M n O_{4}^{-} + 4 H^{+} \to 2 M n O_{4}^{-} + M n O_{2} + 2 H_{2} O

2 K M n O_{4} \to K_{2} M n O_{4} + M n O_{2} + O_{2}

2 M n O_{4}^{-} + 3 M n^{2 +} + 2 H_{2} O \to 5 M n O_{2} + 4 H^{+}

2 C u^{+}

\to

C u^{2 +}

C u^{0}

3 M n O_{4}^{2 -}

4 H^{+}

\to

2 M n O_{4}^{-}

M n O_{2}

2 H_{2} O

2 K M n O_{4}

△ - \to

K_{2} M n O_{4}

M n O_{2}

O_{2}

2 M n O_{4}^{-}

3 M n^{2 +}

2 H_{2} O

⟶

5 M n O_{2}

4 H^{+}

P C l_{3} + C l_{2} \to P C l_{5}

C u + 2 A g N O_{3} \to C u (N O_{3})_{2} + 2 A g

C O_{2} + 2 L i O H \to L i_{2} C O_{3} + H_{2} O

F e C l_{2} + 2 N a O H \to F e (O H)_{2} + 2 N a C l

C u^{+} \to C u^{2 +} + C u

3 M n O_{4}^{- 2} + 4 H^{+} \to 2 M n O_{4}^{-} + M n O_{2} + 2 H_{2} O

2 K M n O_{4} \to K_{2} M n O_{4} + M n O_{2} + O_{2}

2 M n O_{4}^{-} + 3 M n^{+ 2} + 2 H_{2} O \to 5 M n O_{2} + 4 H^{+}

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