Which of the following not show cis-trans -isomerism ?

C H_{3} - H C = C H - C H_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{3} C H_{2} - C H = C H - C H_{2} C H_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{3} - C | C H_{3} = C H - C H_{2} - C H_{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C H_{3} - C H | C H_{3} - C H = C H - C H_{2} - C H_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $C H_{3} - C | C H_{3} = C H - C H_{2} - C H_{3}$
${C H}_{3} - C H | = C H - {C H}_{2} - {C H}_{3}$
${C H}_{3}$
It doesn't show cis-trans isomerism because the double bonded carbon has the same group.
So, it doesn't exhibit this property.

Suggest Corrections

Similar questions

{CH}_{3} - {CH}_{2} - CH = {CH}_{3}

{C H}_{3} C H_{2} {C H}_{2} {C H}_{2} {C H}_{3}, {C H}_{3} - {C H}_{3} | C H - {C H}_{2} C H_{3}, {C H}_{3} - {C H}_{3} | C_{3} - {C H}_{3}

A g N O_{3}

{C H}_{3} - {C H}_{2} - C | H - C H_{2} C H_{3} C H_{2} - C | H C H_{3} - C H_{2} - C H_{3}

C H_{3} - C H | C H_{2} C H_{3} - C H_{3} | C H - C H_{2} - C H_{2} C H_{3} | C H - C H_{3}

Join BYJU'S Learning Program