Question

Which of the following numbers $0.1,0.11,$ ${\left(0.11\right)}^2,\sqrt{0.0001}$ is the greatest ?

• A. $0.11$
• B. $0.1$
• C. ${0.11}^2$
• D. None of these

Answer 1

Answer: (A)

$0.11$

Consider the given numbers and find their values as follows:

$0.100.11{\left(0.11\right)}^2=0.11\times 0.11=0.0121\sqrt{0.0001}=\sqrt{\frac{1}{10000}}=\sqrt{\frac{1^2}{{100}^2}}=\frac{1}{100}=0.010$

Now from the above values we conclude that:

$0.11<0.10<0.0121<0.010$

Hence, $0.11$ is the greatest number.