Which of the following numbers are not perfect cubes?

216

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64

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1000

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100

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Solution

The correct option is D $100$
Option A:- $216 = 6^{3}$

Option B:- $64 = 8^{3}$

Option C:- $1000 = 10^{3}$

Option D:- $100 = 10^{2}$

Therefore, $100$ is not the perfect cube.

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Similar questions

(1) 216, (2) 128, (3) 1000, (4) 100, (5) 46656

216

128

1000

Which of the following are not perfect cubes?
(i) $216$
(ii) $128$
(iii) $1000$
(iv) $100$
(v) $46656$

128

100

64

125

72

625

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