Question

Which of the following numbers are perfect squares ?

• A. 121
• B. 1057
• C. 23453
• D. 7928
• E. 222222

Answer 1

The correct option is A 121

$\left(a\right)121$

$\because$ The ending digit is $1$

$\therefore$ it may or may not be a square number.

$\because 11\times 11=121$

Hence $121$ is a square number.

$\left(b\right)1057$

$\because$ The ending digit is $7$(which is not one of $0,1,4,5,6$ or $9$)

$\therefore 1057$ cannot be a square number.

$\left(c\right)23453$

$\because$The ending digit is $3$(which is not one of $0,1,4,5,6$ and $9$)

$\therefore 23453$ cannot be a square number.

$\left(d\right)7928$

$\because$The ending digit is $8$(which is not one of $0,1,4,5,6$ and $9$)

$\therefore 7928$ cannot be a square number.

$\left(e\right)222222$

$\because$ the ending digit is $2$(which is not one of $0,1,4,5,6$ or $9$)

$\therefore 222222$ cannot be a square number.