Question

Which of the following numbers is completely divisible by 3?

• A. 327
• B. 428
• C. 124
• D. 305

Answer 1

The correct option is A 327

A number is divisible by 3 if the sum of all the digits in the number is divisible by 3.

327
(3 + 2 + 7) = 12.
12 is divisible by 3
$\therefore$ 327 is divisible by 3.

428
(4 + 2 + 8) = 14.
14 is not divisible by 3.
$\therefore$ 428 is not divisible by 3.

124
(1 + 2 + 4) = 7.
7 is not divisible by 3.
$\therefore$ 124 is not divisible by 3.

305
(3 + 0 + 5) = 8.
8 is not divisible by 3.
$\therefore$ 305 is not divisible by 3.

Therefore, out of the given numbers 327 is divisible by 3.