Question

Which of the following numbers is completely divisible by 3?

• A. 327
• B. 428
• C. 124
• D. 305

Answer 1

The correct option is A 327

A number is divisible by 3 if the sum of all the digits in the number is divisible by 3.

In case of first option:
Number = 327
Sum of the digits = 3 + 2 + 7 = 12
12 is divisible by 3.
$\therefore$ 327 is divisible by 3.

In case of the second option:
Number = 428
Sum of the digits = 4 + 2 + 8 = 14
14 is not divisible by 3.
$\therefore$ 428 is not divisible by 3.

In case of the third option:
Number = 124
Sum of the digits = 1 + 2 + 4 = 7
7 is not divisible by 3.
$\therefore$ 124 is not divisible by 3.

In case of the fourth option:
Number = 305
Sum of the digits = 3 + 0 + 5 = 8
8 is not divisible by 3.
$\therefore$ 305 is not divisible by 3.

Therefore, out of the given numbers 327 is divisible by 3.