Which of the following numbers is the largest?

{(2 + 2 + 2)}^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{(2 + 2^{2})}^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{(2 \times 2 \times 2)}^{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 + 2^{2} + {(2)}^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C ${(2 \times 2 \times 2)}^{2}$
$A : (2 + 2 + 2)^{2} = 6^{2} = 36$
$B : (2 + 2^{2})^{2} = (2 + 4)^{2} = 6^{2} = 36$
$C : (2 \times 2 \times 2)^{2} = 8^{2} = 64$
$D : 2 + 2^{2} + (2)^{2} = 2 + 4 + 4 = 10$

Suggest Corrections

Similar questions

2^{2} + 22^{2} + 222^{2} + . . . . . .

(\frac{9 + 2 \sqrt{22}}{9 - 2 \sqrt{22}} + \frac{9 - 2 \sqrt{22}}{9 + 2 \sqrt{22}}) = ?

n

2 + 22 + 222 + . . . .

\frac{1^{2}}{1!} + \frac{1^{2} + 2^{2}}{2!} + \frac{1^{2} + 2^{2} + 3^{2}}{3!} + . . . .

2^{2} + 22^{2} + 222^{2} + 2222^{2} + . . . . (222 . . . .49 t w o s)^{2}

Join BYJU'S Learning Program