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Question

Which of the following numbers when divided by 32, 64 & 128 leaves the remainder as 8.


A

1024

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B

1034

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C

512

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D

1032

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Solution

The correct option is D

1032


32 = 2×2×2×2×2

64 = 2×2×2×2×2×2

128 = 2×2×2×2×2×2×2

LCM of 32, 64, 128 is 128.

When 512 and1024 are divided by 128 there is no remainder.

1034 leaves a remainder of 10.

1024+8 =1032 will leave a remainder of 8.


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