Question

Which of the following numbers will not have 1(one) at their unit's place?

• A. $(32{)}^2$
• B. $(57{)}^2$
• C. $(69{)}^2$
• D. $(321{)}^2$
• E. $(97{)}^2$
• F. $(265{)}^2$
• G. $(2091{)}^2$

Answer 1

Answer: (A), (B), (E), (F)

$(32{)}^2$
$(57{)}^2$
$(97{)}^2$
$(265{)}^2$

(A) One's digit of $(32{)}^2$ = One's digit of $2^2$ = $4$
(B) One's digit of $(57{)}^2$ =One's digit of $7^2$ = $9$
(C) One's digit of $(69{)}^2$ = One's digit of $9^2$ = $1$
(D) One's digit of $(321{)}^2$ = One's digit of $1^2$ = $1$
(E) One's digit of $(97{)}^2$ = One's digit of $7^2$ = $9$
(F) One's digit of $(265{)}^2$ = One's digit of $5^2$ = $5$
(G) One's digitof $(2091{)}^2$ = One's digit of $1^2$ = $1$

Hence, the $\left(A\right),\left(B\right),\left(E\right)$ and $\left(F\right)$ are the correct options.