Question

Which of the following on reaction with acetylene $(CH\equiv CH)$ produce gas(es)?
$I.K$ in liquid ${NH}_3$ $II.\stackrel{\ominus }{{NH}_2}$
$III.\stackrel{\ominus }{C{H}_3}$ $IV.\stackrel{\ominus }{OH}$

• A. $\left(I\right),\left(II\right)$ and $\left(III\right)$
• B. $\left(I\right),\left(II\right)$ and $\left(IV\right)$
• C. $\left(I\right),\left(III\right)$ and $\left(IV\right)$
• D. $\left(II\right),\left(III\right)$ and $\left(IV\right)$

Answer 1

The correct option is A $\left(I\right),\left(II\right)$ and $\left(III\right)$

$I.HC\equiv CH\underset{Birchred.C\equiv C\Rightarrow (C=C)}{\overset{Kinliq.{NH}_3}{\to }}{H}_{2}C={CH}_2$(Gas)

$II.HC\equiv CH+\stackrel{\ominus }{N}{H}_2⟶CH\equiv C^{\ominus }+{NH}_3$(Gas)

$III.HC\equiv CH+\stackrel{\ominus }{C{H}_3}⟶HC\equiv C^{\ominus }+{CH}_4$ (Gas)

$IV.HC\equiv CH+\stackrel{\ominus }{O}H⟶HC\equiv C^{\ominus }+H_{2}O$ (liquid)
Except $O{H}^{-}$ all produces gas. Hence option A is correct.