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Anionic Radius

Which of the ...

Question

Which of the following option is correct about the species in terms of increasing atomic (or ionic) radius:
$S r, P, M g, {M g}^{2 +}$

{M g}^{2 +} < P < M g < S r

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P < M g < S r < M g^{2 +}

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M g^{2 +} < S r < M g < P

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none of the above

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Solution

The correct option is A ${M g}^{2 +} < P < M g < S r$
The atomic radius of a cation is smaller than its neutral atom due to effective nuclear charge. So $M g^{2 +}$ ion has least atomic size. $M g$ and $S r$ belong to group II while $P$ is group 15 element in the periodic table. Atomic radii decrease along the period while increases in moving down the group. Since $P$ is present in the same period of $M g$ atom so $M g$ has a higher atomic radius in that period while $S r$ is present in the II group below the $M g$ atom so $S r$ is greater in atomic size.

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Similar questions

25^{o}

S r_{(s)} + M g_{(a q)}^{2 +} \to S r_{(a q)}^{2 +} + M g_{(s)}

E_{M g^{2 +} / M g}^{o} = - 2.37

E_{{S r}^{2} + / S r}^{o} = - 2.89

I

A l > S i > P > C l

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B e < M g < C a < S r

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I < B r < C l < F

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Arrange the following in order of increasing radii :

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B e^{2 +}

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4 \times 10^{12}

25^{o} C

E^{o}

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2 = 0.3

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