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Question

Which of the following option is correct for ionic radii?

A
Ti+4 < Mn+7
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B
35Cl < 37Cl
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C
K+ > Cl
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D
P+3 > P+5
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Solution

The correct option is D P+3 > P+5
Higher the (+ve) charge smaller the radii will be.
In option (a) as charge on Mn is greater than Ti, radius of Mn should be smaller than Ti. So option (a) is wrong.
In option (b) the radius should be same as the atomic number is same in both the isotopes.
In option (c) the charge on K+ is greater than Cl, so radius of K+ should be smaller than Cl.
In option (d) the radius of P+3 is larger as the charge is smaller. So, option (d) is correct.

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