Which of the following option is the correct order for the basic strength of metallic hydroxides ?

C a (O H)_{2} < A l (O H)_{3} < L u (O H)_{3} < C e (O H)_{3}

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A l (O H)_{3} < L u (O H)_{3} < C e (O H)_{3} < C a (O H)_{2}

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L u (O H)_{3} < C e (O H)_{3} < A l (O H)_{3} < C a (O H)_{2}

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L u (O H)_{3} < C e (O H)_{3} < C a (O H)_{2} < A l (O H)_{3}

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Solution

The correct option is B $A l (O H)_{3} < L u (O H)_{3} < C e (O H)_{3} < C a (O H)_{2}$
As the size of metal atom increases, $M - O$ bond length increases and the tendency to lose $- O H$ group increases, i.e., basicity increases.

The order of size of given metallic elements is :
$A l^{3 +} < L u^{3 +} < C e^{3 +} < C a^{2 +}$

Thus, the order of basic strength is :
$A l (O H)_{3} < L u (O H)_{3} < C e (O H)_{3} < C a (O H)_{2}$

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