Which of the following option is the standard form of the mentioned quadratic equation?
$2 z - \frac{5}{z} = z - 6$

z^{2} + 6 z = 0

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z^{2} - 6 z - 5 = 0

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z^{2} + 6 z - 5 = 0

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z^{2} + 6 z + 5 = 0

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Solution

The correct option is C $z^{2} + 6 z - 5 = 0$
Given,

$2 z - \frac{5}{z} = z - 6$

$\Rightarrow \frac{2 z^{2} - 5}{z} = z - 6$

$\Rightarrow 2 z^{2} - 5 = z^{2} - 6 z$

$\Rightarrow 2 z^{2} - z^{2} + 6 z - 5 = 0$

$\Rightarrow z^{2} + 6 z - 5 = 0$ (Standard form of given quadratic equation)

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