Which of the following option is the standard form of the mentioned quadratic equation?
$x^{2} = - 7 - \sqrt{10} x$

x^{2} + \sqrt{10} x + 7 = 0

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x^{2} - \sqrt{10} x + 7 = 0

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x^{2} + \sqrt{10} x - 7 = 0

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x^{2} - \sqrt{10} x - 7 = 0

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Solution

The correct option is A $x^{2} + \sqrt{10} x + 7 = 0$
Given,
$x^{2} = - 7 - \sqrt{10} x$

Standard form of mentioned quadratic equation will be,

$x^{2} + \sqrt{10} x + 7 = 0$

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