Which of the following option is the standard form of the mentioned quadratic equation?
$y^{2} - 9 = 13 y$

y^{2} + 13 y - 9 = 0

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y^{2} - 13 y + 9 = 0

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y^{2} + 13 y + 9 = 0

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y^{2} - 13 y - 9 = 0

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Solution

The correct option is D $y^{2} - 13 y - 9 = 0$
Given,
$y^{2} - 9 = 13 y$

Standard form of mentioned quadratic equation will be,

$y^{2} - 13 y - 9 = 0$

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