Which of the following options are correct for isoelectronic pairs?

H_{2}, H D

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C O, N_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

H C l, H_{2} S

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

D_{2} O, N e

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct options are
A $H_{2}, H D$
B $C O, N_{2}$
C $D_{2} O, N e$
D $H C l, H_{2} S$
(a) $H_{2}, H D \to$ 2 electron

(atomic number of $H$ & $D$ is 1) $H_{2}, H D$ have $2$ electrons each.
(b) $C O, N_{2} \to$ $14$ electron

(atomic number of $C - 6, O - 8$ & $N - 7$ ) $C O, N_{2}$ have $14$ electrons each.
(c) $H C l, H_{2} S \to$ $18$ electron

(atomic number of $H - 1, C l - 17$ & $S - 16$ ) $H C l, H_{2} S$ have $18$ electrons each.
(d) $D_{2} O, N e \to$ $10$ electron

(atomic number of $D - 1, O - 8$ & $N e - 10$ ). $D_{2} O, N e$ have $10$ electrons each.
Hence A,B,C & D are correct.

Suggest Corrections

Similar questions

H_{2} S

In which of the following equilibria, the value of $K_{P}$ is less than $K_{C}$

Balance the following equations :

(a) $N_{2} + H_{2} \to N H_{3}$

(b) $H_{2} + O_{2} \to H_{2} O$

(d) $C O + O_{2} \to C O_{2}$

(e) $Z n + H C I \to Z n C l_{2} + H_{2}$

H_{2} S

0.2 M

H C l

800^{\circ} C

2 N O + H_{2} \to N_{2} + H_{2} O

H_{2}

[H_{2}] = 1.5 \times 10^{- 3} M a n d [N O] = 1.1 \times 10^{- 3} M

Join BYJU'S Learning Program