Which of the following options are equal to tan 2 A - 2 A -2 -A- 2 A -cosec2 AB- tan 2 A - 2 AC- 2 A -cosec2 AD- -1-cos 2 A -sin 2 A

The correct options are A sec^2A.cosec^2A C sec^2A+cosec^2A D = 1/cos^2A.sin^2A tan^2A+cot^2A+2 = 1+tan^2A+1+cot^2A = sec^2A+cosec^2A......1+tan^2A=sec^2A and ...

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Byju's Answer

Standard X

Mathematics

Trigonometric Identities

Which of the ...

Question

Which of the following options are equal to $t a n^{2} A + c o t^{2} A + 2$ ?

$s e c^{2} A . c o s e c^{2} A$

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$t a n^{2} A . c o t^{2} A$

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$s e c^{2} A + c o s e c^{2} A$

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= $\frac{1}{c o s^{2} A . s i n^{2} A}$

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Solution

The correct options are
A
$s e c^{2} A . c o s e c^{2} A$

C
$s e c^{2} A + c o s e c^{2} A$

D
= $\frac{1}{c o s^{2} A . s i n^{2} A}$

$t a n^{2} A + c o t^{2} A + 2$

= $1 + t a n^{2} A + 1 + c o t^{2} A$

= $s e c^{2} A + c o s e c^{2} A$ ...... $1 + t a n^{2} A = s e c^{2} A$ and $1 + c o t^{2} A = c o s e c^{2} A$

= $\frac{1}{c o s^{2} A} + \frac{1}{s i n^{2} A}$

= $\frac{s i n^{2} A + c o s^{2} A}{c o s^{2} A . s i n^{2} A}$ .... $s i n^{2} A + c o s^{2} A = 1$

= $\frac{1}{c o s^{2} A . s i n^{2} A}$

= $s e c^{2} A . c o s e c^{2} A$

Suggest Corrections

Which of the following options are equal to tan2A+cot2A+2?

The correct options are A sec2A.cosec2A C sec2A+cosec2A D = 1cos2A.sin2A tan2A+cot2A+2 = 1+tan2A+1+cot2A = sec2A+cosec2A......1+tan2A=sec2A and 1+cot2A=cosec2A = 1cos2A+1sin2A = sin2A+cos2Acos2A.sin2A....sin2A+cos2A=1 = 1cos2A.sin2A = sec2A.cosec2A

Which of the following options are equal to $t a n^{2} A + c o t^{2} A + 2$ ?