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Question

Which of the following options is equal to cot θ+cosec θ1cot θcosec θ+1


A

1

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B

sin θ1cos θ

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C

1+cos θsin θ

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D

cotθ+cosecθ

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Solution

The correct option is D

cotθ+cosecθ


=cot θ+cosec θ1cot θcosec θ+1

=cot θ+cosec θ(cosec2θcot2θ)cot θcosec θ+1

=(cot θ+cosec θ)(cosec θcot θ)(cosec θ+cot θ)cot θcosec θ+1

=(cot θ+cosec θ)(1cosec θ+cot θ)(cot θcosec θ+1)

=cot θ+cosec θ

=cos θsin θ+1sin θ

=1+cos θsin θ

=(1+cos θ)(1cos θ)sinθ(1cos θ) ....[Multiplying numerator and denominator by 1cosθ ]

=1cos2θsinθ(1cos θ)

=sin2θsinθ(1cos θ)

=sin θ1cos θ


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