The correct option is D 5x−5y
2(3x−3y)=(2×3x)+(2×(−3y))
=6x−6y
Option A is equivalent to the expression 2(3x−3y).
Changing the order does not change the value of the addition, so 6x−6y can be written as −6y+6x.
Option B is also equivalent to the expression 2(3x−3y).
3(2x−2y)=(3×2x)+(3×(−2y))=6x−6y=2(3x−3y)
Option C is also equivalent to the expression 2(3x−3y).
In 5x−5y, none of the terms matches with 6x−6y.
⇒5x−5y and 2(3x−3y) are not equivalent expressions.
Option D is correct.