Which of the following options regarding order of ebullioscopic constant, $K_{b}$ is correct?

K_{b C_{6} H_{6}} > K_{b C_{2} H_{5} - O - C_{2} H_{5}} > K_{b C S_{2}} > K_{b C C l_{4}}

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K_{b C C l_{4}} > K_{b C_{6} H_{6}} > K_{b C S_{2}} > K_{b C_{2} H_{5} - O - C_{2} H_{5}}

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K_{b C S_{2}} > K_{b C_{2} H_{5} - O - C_{2} H_{5}} > K_{b C_{6} H_{6}} > K_{b C C l_{4}}

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K_{b C_{2} H_{5} - O - C_{2} H_{5}} > K_{b C_{6} H_{6}} > K_{b C S_{2}} > K_{b C C l_{4}}

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Solution

The correct option is B $K_{b C C l_{4}} > K_{b C_{6} H_{6}} > K_{b C S_{2}} > K_{b C_{2} H_{5} - O - C_{2} H_{5}}$
more than mass more eballiosopie constant
$C Q_{4} = 153.82$
$C S_{2} - 76.139$
$C_{2} H_{5} - 0 - C_{2} H_{2} - 74.12$
$C_{6} H_{6} - 78.11$

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IUPAC name of the $C H_{3} - O - C_{2} H_{5}$ is:

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