Question

Which of the following options regarding sulphur is correct?

(a) Density of monoclinic sulphur is more than rhombic sulphur due to the arrangement of puckered rings.
(b) In a puckered ring one sulphur is bonded with 2 other sulphur atoms.
(c) The melting point of rhombic sulphur is considered as transition temperature of sulphur.
(d) Flower of sulphur is the vapour form of sulphur.

• A. only b
• B. $a$ and $b$
• C. $b$ and $c$
• D. $a,b$ and $d$

Answer 1

Answer: (A)

only b

(a) (c) and (d) are wrong.

(a) The density of rhombic sulphur is more than monoclinic sulphur.

(c) Rhombic sulphur melts at about ${118}^{\circ }C$, while its transition temperature is ${95.6}^{\circ }C$.

(d) Flower of sulphur is not the vapour form of sulphur. It is a bright-yellow powdered form of sulphur.

Thus only statement b is correct thus the correct option is Option A.