Question 18

Which of the following order of energies of mlecular orbitals of $N_{2}$ is correct?

(a) $(π 2 p_{y}) < (σ 2 p_{z}) < (π^{} 2 p_{x}) \approx (π^{} 2 p_{y})$

(b) $(π 2 p_{y}) > (σ 2 p_{z}) > (π^{} 2 p_{x}) \approx (π^{} 2 p_{y})$

(c) $(π 2 p_{y}) < (σ 2 p_{z}) < (π^{} 2 p_{x}) \approx (π^{} 2 p_{y})$

(d) $(π 2 p_{y}) > (σ 2 p_{z}) < (π^{} 2 p_{x}) \approx (π^{} 2 p_{y})$

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Solution

Answer: (a). $(π 2 p_{y}) < (σ 2 p_{z}) < (π^{} 2 p_{x}) \approx (π^{} 2 p_{y})$

The correct increasing order of energies of molecular orbitals of

$N_{2}$ is given below $σ 1 s < σ^{} 1 s < σ 2 s < σ^{} 2 s < (π 2 p_{x} \approx π 2 p_{y}) < σ 2 p_{z} < (π^{} 2 p_{x} \approx π^{} 2 p_{y}) < σ^{*} 2 p_{z}$

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Similar questions

Q. When the

O_{2}

molecule becomes the

O_{2}^{-}

ion, the electron adds on to which one of the following orbitals?

Which of the following represent the correct electronic configuration of $O_{2}$ ?

Correct sequence of energy levels in N $_{2}$ molecule

(i)

The energy of $σ 2 p_{z}$ molecular orbital is greater than $π 2 p_{x} and π 2 p_{y}$ molecular orbitals in nitrogen molecule. Write the complete sequence of energy levels in the increasing order of energy in the molecule. Compare the relative stability and the magnetic behaviour of the following species.

$N_{2}$

(ii) $N_{2}^{+}$

(iii) $N_{2}^{-}$

(iv) $N_{2}^{2 +}$

Q. The relative energies of molecular orbitals are found to be in increasing order as follows-

σ (1 s) < σ^{*} (1 s) < σ (2 s) < σ^{*} (2 s) < [π (2 p_{y}) π (2 p_{z})] < σ (2 p_{x}) < [π^{*} (2 p_{y}) π^{*} (2 p_{z})] < σ^{*} (2 p_{x})

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Question 18 Which of the following order of energies of mlecular orbitals of N2 is correct? (a)(π2py)<(σ2pz)<(π∗2px)≈(π∗2py) (b) (π2py)>(σ2pz)>(π∗2px)≈(π∗2py) (c) (π2py)<(σ2pz)<(π∗2px)≈(π∗2py) (d) (π2py)>(σ2pz)<(π∗2px)≈(π∗2py)

Answer: (a). (π2py)<(σ2pz)<(π∗2px)≈(π∗2py) The correct increasing order of energies of molecular orbitals of N2 is given below σ1s<σ∗1s<σ2s<σ∗2s<(π2px≈π2py)<σ2pz<(π∗2px≈π∗2py)<σ∗2pz