Which of the following order of energies of molecular orbitals of $N_{2}$ is correct?

(π 2 p_{y}) < (σ 2 p_{x}) < (π^{*} 2 p_{x}) \approx (π^{*} 2 p_{y})

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(π 2 p_{y}) > (σ 2 p_{x}) > (π^{*} 2 p_{x}) \approx (π^{*} 2 p_{y})

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(π 2 p_{y}) < (σ 2 p_{x}) > (π^{*} 2 p_{x}) \approx (π^{*} 2 p_{y})

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(π 2 p_{y}) > (σ 2 p_{x}) < (π^{*} 2 p_{x}) \approx (π^{*} 2 p_{y})

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Solution

The correct option is A $(π 2 p_{y}) < (σ 2 p_{x}) < (π^{} 2 p_{x}) \approx (π^{} 2 p_{y})$

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Similar questions

σ (1 s) < σ^{*} (1 s) < σ (2 s) < σ^{*} (2 s) < [π (2 p_{y}) π (2 p_{z})] < σ (2 p_{x}) < [π^{*} (2 p_{y}) π^{*} (2 p_{z})] < σ^{*} (2 p_{x})

Correct sequence of energy levels in N $_{2}$ molecule

O_{2}

O_{2}^{-}

σ_{2 S}

L i_{2}

σ^{*} 1 s, σ^{*} 2 s, σ 1 s, π 2 p_{y}, π^{*} 2 p_{x}, π^{*} 2 p_{z}, π 2 p_{z}

π

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