Which of the following order of relative strength of acids is correct?

F {C H}_{2} C O O H > C l {C H}_{2} C O O H > B r {C H}_{2} C O O H > {C H}_{3} C O O H

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

{C H}_{3} C O O H > B r {C H}_{2} C O O H > C l {C H}_{2} C O O H > F {C H}_{2} C O O H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B r {C H}_{2} C O O H > C l {C H}_{2} C O O H > F {C H}_{2} C O O H > {C H}_{3} C O O H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H {C H}_{2} C O O H > {C H}_{3} C O O H > B r {C H}_{2} C O O H > C l {C H}_{2} C O O H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $F {C H}_{2} C O O H > C l {C H}_{2} C O O H > B r {C H}_{2} C O O H > {C H}_{3} C O O H$
The acidic strength depends on the stability of the resulting carboxylate ion.
The presence of electron donating groups enhance the negative charge on carboxylate ion and thus decrease the stability of acids and thus make the acid less acidic. Thus presence of electron withdrawing groups which withdraws the electrons from negatively charged oxygen of carboxylate results in more stability and hence make the acid more acidic.

$R C O O H \to R C O O^{-} + H^{+}$

Thus the order is :
$F C H_{2} C O O H > C l C H_{2} C O O H > B r C H_{2} C O O H > C H_{3} C O O H$

as $C H_{3}$ is electron donating , $C l, B r a n d F$ are electron withdrawing in nature where $F$ is more electron withdrawing due to more electronegativity than $C l$ and $B r$ is least electronegative.
Hence option (A) is correct.

Suggest Corrections

Similar questions

p K_{a}

C F_{3} C O O H, C C l_{3} C O O H, H C C l_{2} C O O H, N O_{2} C H_{2} C O O H, F C H_{2} C O O H, C l C H_{2} C O O H, B r C H_{2} C O O H, H C O O H, C l C H_{2} C H_{2} C O O H, C_{6} H_{5} C O O H, C_{6} H_{5} C H_{2} C O O H, C H_{3} C O O H, C H_{3} C H_{2} C O O H

{C l}_{3} C C O O H > {C l}_{2} C H C O O H > C l {C H}_{2} C O O H

{C H}_{3} C H_{2} C O O H > {(C H}_{3})_{2} C H C O O H > {(C H}_{3})_{3} C C O O H

F_{2} C H_{2} C O O H > F C H_{2} C O O H > C l {C H}_{2} C O O H

C l_{3} C C O O H > C l_{2} C H C O O H > C l C H_{2} C O O H

C l_{3} C C O O H > C l_{2} C H C O O H > C l C H_{2} C O O H

C H_{3} C H_{2} C O O H > (C H_{3})_{2} C H C O O H > (C H_{3})_{3} C . C O O H

$C H_{3} C O C H_{2} C l O H^{-}, C l_{2} - ---- \to$ Product P is

Join BYJU'S Learning Program