Which of the following order of solubility in water is/are correct ?

B e C_{2} O_{4} > B a C_{2} O_{4}

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N a H C O_{3} > K H C O_{3}

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N a C l > K C l

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B e F_{2} > B a F_{2}

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Solution

The correct options are
C $N a C l > K C l$
D $B e F_{2} > B a F_{2}$
The correct solubility orders are
(A) $B e C_{2} O_{4} < B a C_{2} O_{4}$
(B) $N a H C O_{3} < K H C O_{3}$ The solubility increases from Li to Cs in alkali metal group.
(C) $N a C l > K C l$
(D) $B e F_{2} > B a F_{2}$

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Similar questions

N a H C O_{3}, K H C O_{3}, M g (H C O_{3})_{2}, C a (H C O_{3})_{2}

L i F, B e F_{2}, N a_{3} P O_{4}, K_{3} P O_{4}, B a F_{2}, M g F_{2}, L i_{3} P O_{4}, N a F, C s F, C a F_{2}, M g_{3} (P O_{4})_{2}

K C l, K B r, K I

Assertion (A): Solvay process is used for the preparation of $N a H C O_{3}$ but not for $K H C O_{3}$

Reason (R): Solubility of $K H C O_{3}$ is more than $N a H C O_{3}$ in water

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